CAT 2017Slot 2QAQuestion & Solution
Question
If f(ab) = f(a)f(b) for all positive integers a and b, then the largest possible value of f(1) is
Solution
1. Concept Used
- Topic: Functional Equations — Multiplicative Functions
- Formula: $$ f(ab) = f(a) \cdot f(b) $$
2. Calculation
We are given that $$f(ab) = f(a) \cdot f(b)$$ holds for all positive integers $$a$$ and $$b$$.
To find $$f(1)$$, substitute $$a = 1$$ and $$b = 1$$ into the functional equation:
$$f(1 \cdot 1) = f(1) \cdot f(1)$$
$$f(1) = [f(1)]^2$$
This gives us a simple quadratic equation in $$f(1)$$:
$$[f(1)]^2 - f(1) = 0$$
$$f(1)\bigl(f(1) - 1\bigr) = 0$$
So the two possible values are:
$$f(1) = 0 \quad \text{or} \quad f(1) = 1$$
Among these two solutions, the largest value is $$f(1) = 1$$. Note that if $$f(1) = 0$$, the functional equation would force $$f(n) = f(n \cdot 1) = f(n) \cdot f(1) = 0$$ for all positive integers $$n$$, making $$f$$ identically zero — a trivial and less interesting solution. The non-trivial solution $$f(1) = 1$$ is consistent with all multiplicative functions (e.g., $$f(n) = n^k$$).
3. Solution
Answer = 1 ✅
The largest possible value of $$f(1)$$ is 1.
