CAT 2018

Slot 1

DILR

Question & Solution

It is given that a satellite serving either B, or C, or S does not serve O. So we can say that it's basically 3 satellites broadcasting (B), communication (C), surveillance (S) which can have intersections. Those satellites which are not part of any category are placed in others. We can draw the Venn diagram as follows. 

1. The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1.
2. The number of satellites serving all three of B, C, and S is 100.
3. The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B.
4. The number of satellites serving O is the same as the number of satellites serving both C and S but not B.

Let '10x' be the number of satellites exclusively serving B. Then, the number of satellites exclusively serving C and S = 0.30*10x = 3x

Let 'y' be the number of satellites serving others(O).

Let 'z' be the number of satellites serving B, C but not S. Since the numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1. Therefore, we can can say that number of satellites serving B, S but not C = z.

It is given that 

$\Rightarrow$ 10x+2z+2y+6x+100 = 1600

$\Rightarrow$ 8x+z+y = 750 ... (1)

The numbers of satellites serving B, C, and S (though maybe not exclusively) are in the ratio 2:1:1.

$\Rightarrow$ $\dfrac{10x+2z+100}{z+100+3x+y} = \dfrac{2}{1}$

$\Rightarrow$ $10x+2z+100=2(z+100+3x+y)$

$\Rightarrow$ $4x=100+2y$

$\Rightarrow$ $2x=50+y$

$\Rightarrow$ $y=2x-50$   ... (2)

We can substitute this in equation (1)

$\Rightarrow$ 8x+z+2x - 50 = 750

$\Rightarrow$ z = 800 - 10x    ... (3)

Let us define boundary condition for x, 

$\Rightarrow$ 2x - 50 $\geq$ 0

$\Rightarrow$ x $\geq$ 25

Also,  800 - 10x $\geq$ 0

$\Rightarrow$ x $\leq$ 80

Therefore, we can say that x $\epsilon$ [25, 80].

The number of satellites serving C = 800 - 10x + 100 + 3x + 2x - 50 = 850 - 5x

At x = 25, The number of satellites serving C = 850 - 5x = 850 - 5*25 = 725 

At x = 80, The number of satellites serving C = 850 - 5x = 850 - 5*80 = 450

Hence, we can say that the number of satellites serving C must be between 450 and 725. Hence, option C is the correct answer. 

It is given that a satellite serving either B, or C, or S does not serve O. So we can say that it's basically 3 satellites broadcasting (B), communication (C), surveillance (S) which can have intersections. Those satellites which are not part of any category are placed in others. We can draw the Venn diagram as follows. 

1. The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1.
2. The number of satellites serving all three of B, C, and S is 100.
3. The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B.
4. The number of satellites serving O is the same as the number of satellites serving both C and S but not B.

Let '10x' be the number of satellites exclusively serving B. Then, the number of satellites exclusively serving C and S = 0.30*10x = 3x

Let 'y' be the number of satellites serving others(O).

Let 'z' be the number of satellites serving B, C but not S. Since the numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1. Therefore, we can can say that number of satellites serving B, S but not C = z.

It is given that 

$\Rightarrow$ 10x+2z+2y+6x+100 = 1600

$\Rightarrow$ 8x+z+y = 750 ... (1)

The numbers of satellites serving B, C, and S (though maybe not exclusively) are in the ratio 2:1:1.

$\Rightarrow$ $\dfrac{10x+2z+100}{z+100+3x+y} = \dfrac{2}{1}$

$\Rightarrow$ $10x+2z+100=2(z+100+3x+y)$

$\Rightarrow$ $4x=100+2y$

$\Rightarrow$ $2x=50+y$

$\Rightarrow$ $y=2x-50$   ... (2)

We can substitute this in equation (1)

$\Rightarrow$ 8x+z+2x - 50 = 750

$\Rightarrow$ z = 800 - 10x    ... (3)

Let us define boundary condition for x, 

$\Rightarrow$ 2x - 50 $\geq$ 0

$\Rightarrow$ x $\geq$ 25

Also,  800 - 10x $\geq$ 0

$\Rightarrow$ x $\leq$ 80

Therefore, we can say that x $\epsilon$ [25, 80].

The number of satellites serving B exclusively = 10x. This will be the minimum when 'x' is the minimum. 

At x$_{min}$ = 25, The number of satellites serving B exclusively  = 10*25 =250. Hence, option A is the correct answer. 

It is given that a satellite serving either B, or C, or S does not serve O. So we can say that it's basically 3 satellites broadcasting (B), communication (C), surveillance (S) which can have intersections. Those satellites which are not part of any category are placed in others. We can draw the Venn diagram as follows. 

1. The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1.
2. The number of satellites serving all three of B, C, and S is 100.
3. The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B.
4. The number of satellites serving O is the same as the number of satellites serving both C and S but not B.

Let '10x' be the number of satellites exclusively serving B. Then, the number of satellites exclusively serving C and S = 0.30*10x = 3x

Let 'y' be the number of satellites serving others(O).

Let 'z' be the number of satellites serving B, C but not S. Since the numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1. Therefore, we can can say that number of satellites serving B, S but not C = z.

It is given that 

$\Rightarrow$ 10x+2z+2y+6x+100 = 1600

$\Rightarrow$ 8x+z+y = 750 ... (1)

The numbers of satellites serving B, C, and S (though maybe not exclusively) are in the ratio 2:1:1.

$\Rightarrow$ $\dfrac{10x+2z+100}{z+100+3x+y} = \dfrac{2}{1}$

$\Rightarrow$ $10x+2z+100=2(z+100+3x+y)$

$\Rightarrow$ $4x=100+2y$

$\Rightarrow$ $2x=50+y$

$\Rightarrow$ $y=2x-50$   ... (2)

We can substitute this in equation (1)

$\Rightarrow$ 8x+z+2x - 50 = 750

$\Rightarrow$ z = 800 - 10x    ... (3)

Let us define boundary condition for x, 

$\Rightarrow$ 2x - 50 $\geq$ 0

$\Rightarrow$ x $\geq$ 25

Also,  800 - 10x $\geq$ 0

$\Rightarrow$ x $\leq$ 80

Therefore, we can say that x $\epsilon$ [25, 80].

It is given that at least 100 of the 1600 satellites were serving O.

$\Rightarrow$ 2x - 50 $\geq$ 100

$\Rightarrow$ x $\geq$ 75

The number of satellites serving S = 100 + 800 - 10x + 2x - 50 + 3x = 850 - 5x

At x$_{min}$ = 75, the number of satellites serving S = 850 - 5*75 = 475

At x$_{max}$ = 80, the number of satellites serving S = 850 - 5*80 = 450

Hence, we can say that the number of satellites serving S must be from 425 to 475. Therefore, we can say that option A is the correct answer.

It is given that a satellite serving either B, or C, or S does not serve O. So we can say that it's basically 3 satellites broadcasting (B), communication (C), surveillance (S) which can have intersections. Those satellites which are not part of any category are placed in others. We can draw the Venn diagram as follows. 

1. The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1.
2. The number of satellites serving all three of B, C, and S is 100.
3. The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B.
4. The number of satellites serving O is the same as the number of satellites serving both C and S but not B.

Let '10x' be the number of satellites exclusively serving B. Then, the number of satellites exclusively serving C and S = 0.30*10x = 3x

Let 'y' be the number of satellites serving others(O).

Let 'z' be the number of satellites serving B, C but not S. Since the numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1. Therefore, we can can say that number of satellites serving B, S but not C = z.

It is given that 

$\Rightarrow$ 10x+2z+2y+6x+100 = 1600

$\Rightarrow$ 8x+z+y = 750 ... (1)

The numbers of satellites serving B, C, and S (though maybe not exclusively) are in the ratio 2:1:1.

$\Rightarrow$ $\dfrac{10x+2z+100}{z+100+3x+y} = \dfrac{2}{1}$

$\Rightarrow$ $10x+2z+100=2(z+100+3x+y)$

$\Rightarrow$ $4x=100+2y$

$\Rightarrow$ $2x=50+y$

$\Rightarrow$ $y=2x-50$   ... (2)

We can substitute this in equation (1)

$\Rightarrow$ 8x+z+2x - 50 = 750

$\Rightarrow$ z = 800 - 10x    ... (3)

Let us define boundary condition for x, 

$\Rightarrow$ 2x - 50 $\geq$ 0

$\Rightarrow$ x $\geq$ 25

Also,  800 - 10x $\geq$ 0

$\Rightarrow$ x $\leq$ 80

Therefore, we can say that x $\epsilon$ [25, 80].

It is given that the number of satellites serving at least two among B, C, and S is 1200.

$\Rightarrow$ 800 - 10x + 800 - 10x + 2x -50 + 100 = 1200

$\Rightarrow$ 18x = 450

$\Rightarrow$ x = 25

We can determine number of satellites in each of the following category. Hence, option C is definitely false. Therefore, we can say that option C is incorrect.