CAT 2018 Slot 2 QA Question & Solution
AlgebraHard
Question
Let $t_{1},t_{2}$,... be real numbers such that $t_{1}+t_{2}+…+t_{n} = 2n^{2}+9n+13$, for every positive integer $n \geq 2$. If $t_{k}=103$, then k equals
Solution
It is given that $t_{1}+t_{2}+…+t_{n} = 2n^{2}+9n+13$, for every positive integer $n \geq 2$.
We can say that $t_{1}+t_{2}+…+t_{k} = 2k^{2}+9k+13$ ... (1)
Replacing k by (k-1) we can say that
$t_{1}+t_{2}+…+t_{k-1} = 2(k-1)^{2}+9(k-1)+13$ ... (2)
On subtracting equation (2) from equation (1)
$\Rightarrow$ $t_{k} = 2k^{2}+9k+13 - 2(k-1)^{2}+9(k-1)+13$
$\Rightarrow$ $103 = 4k+7$
$\Rightarrow$ $k = 24$
