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CAT 2018 Slot 2 QA Question & Solution

ArithmeticMedium

Question

The smallest integer n for which $4^{n} > 17^{19}$ holds, is closest to

Options

37
35
33
39

Solution

$4^{n} > 17^{19}$

$\Rightarrow$ $16^{n/2} > 17^{19}$

Therefore, we can say that n/2 > 19

n > 38

Hence, option D is the correct answer.