CAT 2018Slot 2QAQuestion & Solution

GeometryEasy

Question

A chord of length 5 cm subtends an angle of 60° at the centre of a circle. The length, in cm, of a chord that subtends an angle of 120° at the centre of the same circle is

Options

$5\sqrt{3}$

$2\pi$

$8$

$6\sqrt{2}$

Solution

1. Concept Used

  • Topic: Circles — Chord Length and Central Angle
  • Formula: $$ \text{Chord Length} = 2r \cdot \sin\left(\frac{\theta}{2}\right) $$

where $r$ is the radius of the circle and $\theta$ is the central angle subtended by the chord.


2. Calculation

Step 1: Find the radius using the first chord.

We are given that a chord of length $5$ cm subtends a central angle of $60°$. Using the chord-length formula:

$$5 = 2r \cdot \sin\left(\frac{60°}{2}\right) = 2r \cdot \sin(30°) = 2r \cdot \frac{1}{2} = r$$

So the radius $r = 5$ cm.

Step 2: Find the length of the second chord.

Now we need the length of a chord that subtends a central angle of $120°$ at the centre of the same circle (radius $= 5$ cm):

$$\text{Chord Length} = 2r \cdot \sin\left(\frac{120°}{2}\right) = 2 \times 5 \times \sin(60°)$$

$$= 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3} \text{ cm}$$


3. Solution

Answer = Option A

The length of the chord that subtends an angle of $120°$ at the centre is $\mathbf{5\sqrt{3}}$ cm.