CAT 2019 Slot 2 QA Question & Solution
AlgebraMedium
Question
The number of common terms in the two sequences: 15, 19, 23, 27, . . . . , 415 and 14, 19, 24, 29, . . . , 464 is
Options
21
20
18
19
Solution
A: $15, 19, 23, 27, \ldots, 415$
B: $14, 19, 24, 29, \ldots, 464$
Here the first common term = $19$
Common difference = $LCM(5, 4) = 20$
$19 + (n-1)20 \le 415$
$(n-1)20 \le 396$
$(n-1) \le 19.8$
$n=20$
