CAT 2019

Slot 2

QA

Question & Solution

Area of $\triangle ABC = 2 \times \text{Area of the triangle } ABD$

Area of $\triangle ABD = \text{Area of } \triangle AGB + \text{Area of } \triangle BGD$

$\text{Since } \angle AGB = \angle BGD = 90^\circ \text{ (Given)}$

$\text{Area of } \triangle AGB = \frac{1}{2} \times 8 \times 6 = 24$

$\text{Area of } \triangle BGD = \frac{1}{2} \times 6 \times 4 = 12$

$\text{Area of } \triangle ABD = 24 + 12 = 36$

$\text{Area of } \triangle ABC = 2 \times 36 = 72$