CAT 2020 Slot 3 QA Question & Solution
Question
A man buys 35 kg of sugar and sets a marked price in order to make a 20% profit. He sells 5 kg at this price, and 15 kg at a 10% discount. Accidentally, 3 kg of sugar is wasted. He sells the remaining sugar by raising the marked price by p percent so as to make an overall profit of 15%. Then p is nearest to
Options
Solution
Let the cost price of 1kg of sugar = Rs 100
The total cost price of 35 kg = Rs3500
Marked up price per kg = Rs 120
GIven, the final profit is 15% => Final SP of 35 kg = 3500 *1.15 = Rs 4025
First 5 kg's are sold at 20% marked up price => $SP_1=5\cdot100\cdot1.2$ = Rs 600
Next 15 kgs are sold after giving 10% discount => $SP_2=15\cdot100\cdot1.2\cdot0.9\ =\ 1620$
3kgs of sugar got wasted
=> 23 kg of sugar was sold at Rs (600 +1620) = Rs 2220
Remaining 12kg should be sold at Rs 4025 - 2220 = Rs1805
=> SP of 1kg = 1805/12 $\simeq\ 150$
Hence, the seller should further mark up by $\frac{\left(150-120\right)}{120}\cdot100\ =\ 25\%$