CAT 2020 Slot 3 QA Question & Solution
GeometryMedium
Question
In a trapezium $ABCD$, $AB$ is parallel to $DC$, $BC$ is perpendicular to $DC$ and $\angle BAD=45^{0}$. If $DC$ = 5cm, $BC$ = 4 cm,the area of the trapezium in sq cm is
Solution
Given, BC = DE = 4
CD = BE = 5
In triangle ADE, EAD=45^{0}$
$\tan\ 45\ =\ \frac{DE}{AE}$$ => AE = 4
Area of trapezium = Area of rectangle BCDE + Area of triangle AED
= 20 + 8 = 28
