Applyo - College Application Platform

CAT 2023 Slot 1 QA Question & Solution

AlgebraHard

Question

For some positive and distinct real numbers $x, y$ and z, if $\frac{1}{\sqrt{y}+\sqrt{z}}$ is the arithmetic mean of $\frac{1}{\sqrt{x}+\sqrt{z}}$ and $\frac{1}{\sqrt{x}+\sqrt{y}}$, then the relationship which will always hold true, is

Options

$\sqrt{x}, \sqrt{z}$ and $\sqrt{y}$ are in arithmetic progression
y, x and z are in arithmetic progression
x, y and z are in arithmetic progression
$\sqrt{x}, \sqrt{y}$ and $\sqrt{z}$ are in arithmetic progression

Solution

Given that $\dfrac{1}{\sqrt{y}+\sqrt{z}}$ is the arithmetic mean of $\dfrac{1}{\sqrt{x}+\sqrt{z}}$ and $\dfrac{1}{\sqrt{x}+\sqrt{y}}$

=> $\dfrac{2}{\sqrt{\ y}+\sqrt{\ z}}=\dfrac{1}{\sqrt{\ x}+\sqrt{\ z}}+\dfrac{1}{\sqrt{\ x}+\sqrt{\ y}}$

=> $2\left(\sqrt{\ x}+\sqrt{\ z}\right)\left(\sqrt{\ x}+\sqrt{\ y}\right)=\left(\sqrt{\ y}+\sqrt{\ z}\right)\left(\sqrt{\ x}+\sqrt{\ y}+\sqrt{\ x}+\sqrt{\ z}\right)$

=> $2\left(x+\sqrt{\ xy}+\sqrt{\ xz}+\sqrt{\ yz}\right)=2\sqrt{xy}+y+\sqrt{\ yz}+2\sqrt{\ xz}+\sqrt{\ yz}+z$

=> $2x=y+z$

=> y, x, z are in A.P. as x is the arithmetic mean of y and z.