CAT 2024 Slot 2 QA Question & Solution
AlgebraMedium
Question
If $(x + 6\sqrt{2})^{\cfrac{1}{2}} - (x - 6\sqrt{2})^{\cfrac{1}{2}} = 2\sqrt{2}$, then x equals
Solution
Squaring on both sides, we get:
$x+6\sqrt{\ 2}+x-6\sqrt{\ 2}-2\left(x^2-72\right)^{\frac{1}{2}}=8$
$x-\left(x^2-72\right)^{\frac{1}{2}}=4$
Bringing x to the other side, we get:
$-\left(x^2-72\right)^{\frac{1}{2}}=4-x$
Squaring on both sides again, we get:
$x^2-72=16+x^2-8x$
$8x=88$
$x=11$
Therefore, 11 is the correct answer.
