CAT 2025 Slot 2 QA Question & Solution
Question
Ankita is twice as efficient as Bipin, while Bipin is twice as efficient as Chandan. All three of them start together on a job, and Bipin leaves the job after 20 days. If the job got completed in 60 days, the number of days needed by Chandan to complete the job alone, is
Solution
Let Chandan’s one-day work = x.
Then Bipin = 2x and Ankita = 4x.
All three work together for the first 20 days. Their combined daily work = $$x + 2x + 4x = 7x$$.
Work done in 20 days = $$20\times7x = 140x$$.
Bipin leaves after 20 days; Ankita and Chandan continue for the remaining (60-20=40) days.
Their combined daily work = $$4x + x = 5x$$. Work done in 40 days = $$40\times5x = 200x$$.
Total work = $$140x+200x=340x$$.
We know that Chandan does x work in a day. So, the number of days it takes him to finish the work is 340.
Answer: 340 days.