CAT 2025 Slot 2 QA Question & Solution
Number SystemsHard
Question
Suppose a,b,c are three distinct natural numbers, such that $3ac=8(a+b)$. Then, the smallest possible value of $3a+2b+c$ is
Solution
Our task is to minimise $$3a+2b+c$$.
Here, the coefficient for $$c$$ is the minimum.
$$3ac=8(a+b)$$
We know that a, b, and c are natural numbers. So, the product $$ac$$ should definately be a multiple of 8.
Case 1: a = 1, c = 8 and b = 2 $$\Rightarrow$$ 3a+2b+c = 15
Case 2: a = 2, c = 4 and b = 1 $$\Rightarrow$$ 3a+2b+c = 12
So, 12 is the correct answer.
